FarPoint.Win.SpreadJ アセンブリ > FarPoint.Win.Spread.Model 名前空間 > DefaultSheetDataModel クラス : GetDataColumnFromModelColumn メソッド |
'使用法 Dim instance As DefaultSheetDataModel Dim column As Integer Dim value As Integer value = instance.GetDataColumnFromModelColumn(column)
int i; DataTable dt = new DataTable("Testing"); dt.Columns.Add("Number"); dt.Columns.Add("Letter"); dt.Rows.Add(new Object[]{"1", "One"}); dt.Rows.Add(new Object[] {"2", "Two"}); FarPoint.Win.Spread.Model.DefaultSheetDataModel dataModel = new FarPoint.Win.Spread.Model.DefaultSheetDataModel(dt); fpSpread1.ActiveSheet.Models.Data = dataModel; i = dataModel.GetDataColumnFromModelColumn(1); listBox1.Items.Add(i.ToString());
Dim dt As New DataTable("Testing") Dim i As Integer dt.Columns.Add("Number") dt.Columns.Add("Letter") dt.Rows.Add(New Object() {"1", "One"}) dt.Rows.Add(New Object() {"2", "Two"}) Dim dataModel As New FarPoint.Win.Spread.Model.DefaultSheetDataModel(dt) FpSpread1.ActiveSheet.Models.Data = dataModel i = dataModel.GetDataColumnFromModelColumn(1) ListBox1.Items.Add(i.ToString())